1. Passage Reading
2. Verbal Logic
3. Non Verbal Logic
4. Numerical Logic
5. Data Interpretation
6. Reasoning
7. Analytical Ability
8. Quantitative Aptitude
122. c: The correct answer is 1 in 20.
You must draw $20, $5, and $50 since they are the only three bills that total $75.
The odds of drawing one of the needed bills is 1/2. The odds of drawing another
needed bill is 2/5. The odds of drawing the last needed bill is 1/4. When you
multiply the three fractions, you get 2/40 or 1/20.
123. a: The correct answer was 61 out of 125.
First I'll figure out the odds that you will not be found. The probability of one cop
not finding you is 4/5. The probability of three cops not finding you would be 4/5 *
4/5 * 4/5 = 64/125.
This means that 61/125 is the probability that you will be found.
124. a: The correct answer is 169/425.
There are 4 sets of 13 cards of the same suit, so there is a 39/51 chance that the
second card will be a different suit. The probability of the third card being a
different suit than the others is only 26/50 or 13/25. When you multiply 39/51 *
26/50 you get 1014/2550, or 169/425.
125. a: Let x be the side of the smaller square and y be the side of the larger
square.
The statment "A square has a side 5 centimeters shorter than the side of a
second square" may be formulated by
x = y – 5
For the second solution y = 10 / 3, x is negative and cannot be accepted as the length of the side of a square must be positive.
126.
Use b = 26 - a to find b
when a = 11 , b = 15 and when a = 15 , b = 11.
The two numbers are 11 and 15.
127. a: Let x and y be the length and width of the rectangle. Using the formulas for
the area and the perimeter, we can write two equations.
15 = x y and 16 = 2 x + 2 y
Solve the second equation for x
x = 8 - y
Substitute x in the equation 15 = x y by 8 - y to rewrite the equation as
15 = (8 - y) y
Solve for y to find
y = 3 and y = 5
Use x = 8 - y to find x
when y = 3 , x = 5 and when y = 5 , x = 3.
The dimensions of the rectangle are 3 and 5.
128. a: Let x and y be the two numbers such that x is larger than y. The statement
"the larger number is four less than twice the smaller number" may be formulated
by
x = 2y - 4
We use the sum of the two numbers to write a second equation.
x + y = 20
Substitute x by 2y - 4 in x + y = 20 to obtain
2y - 4 + y = 20
Solve for y to find
y = 8 and x = 2y - 4 = 12
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 |
21 | 22 | 23 | 24 | 25 | 26 | 27 | 28 | 29 | 30 | 31 | 32 | 33 | 34 | 35 | 36 | 37 | 38 | 39 | 40 |
41 | 42 | 43 | 44 | 45 | 46 | 47 | 48 | 49 | 50 | 51 | 52 | 53 | 54 | 55 | 56 | 57 | 58 | 59 | 60 |
61 | 62 | 63 | 64 | 65 | 66 | 67 | 68 | 69 | 70 | 71 | 72 | 73 | 74 | 75 | 76 | 77 | 78 | 79 | 80 |
81 | 82 | 83 | 84 | 85 | 86 | 87 | 88 | 89 | 90 | 91 | 92 | 93 | 94 | 95 | 96 | 97 | 98 | 99 | 100 |
101 | 102 | 103 | 104 | 105 | 106 | 107 | 108 | 109 | 110 | 111 | 112 | 113 | 114 | 115 | 116 | 117 | 118 | 119 | 120 |
121 | 122 | 123 | 124 | 125 | 126 | 127 | 128 | 129 | 130 | 131 | 132 | 133 | 134 | 135 | 136 | 137 | 138 | 139 | 140 |
141 | 142 | 143 | 144 | 145 | 146 | 147 | 148 | 149 | 150 | 151 | 152 | 153 | 154 | 155 | 156 | 157 | 158 | 159 | 160 |
161 | 162 | 163 | 164 | 165 | 166 | 167 | 168 | 169 | 170 | 171 | 172 | 173 | 174 | 175 | 176 | 177 | 178 | 179 | 180 |
181 | 182 | 183 | 184 | 185 | 186 | 187 | 188 | 189 | 190 | 191 | 192 | 193 | 194 | 195 | 196 | 197 | 198 | 199 | 200 |
201 | 202 | 203 | 204 | 205 | 206 | 207 | 208 | 209 | 210 | 211 | 212 | 213 | 214 | 215 | 216 | 217 | 218 | 219 | 220 |
221 | 222 | 223 | 224 | 225 | 226 | 227 | 228 | 229 | 230 | 231 | 232 | 233 | 234 | 235 | 236 | 237 | 238 | 239 | 240 |
241 | 242 | 243 | 244 | 245 | 246 | 247 | 248 | 249 | 250 | 251 | 252 | 253 | 254 | 255 | 256 | 257 | 258 | 259 | 260 |
261 | 262 | 263 | 264 | 265 | 266 | 267 | 268 | 269 | 270 | 271 |